Reverse Sample Clauses

Reverse. Estate Planning: Turning Your Poorer Parent into an Asset
Reverse. 4.1 The Customer and the Bank may notify GSB that they have agreed to reverse the transfer of a Working Gas Bundle (each a “WGB Reverse Notice”). These notices, if compliant with and subject to this Article 4 and Article 8 together create a “WGB Reverse”.
Reverse. Split. Buyer shall have effectuated a 1000 to 1 reverse split of its common stock;
Reverse engineering You may not use, copy, emulate, clone, modify, decompile, disassemble, otherwise reverse engineer the SOFTWARE, or any of it's parts, except as provided by this agreement. Any such unauthorized use will result in immediate and automatic termination of this license agreement.
Reverse or “reflexiveindemnities: i.e. Party A indemnifies Party B against losses incurred as a result of Party B’s own acts and/or omissions (e.g. negligence).
Reverse action reverses the link (p, q) to (q, p). Note that whenever this hap- pens, p is staying or p is leaving and p < q. The changes (that is, cases 2 and 3) to a link (p, q) over time form a sequence of links (p, q) = (p0, q0), (p1, q1), (p2, q2), . . . that we call the trace of (p, q). The cases listed above imply the following Monotonicity lemma.Lemma 3. (Monotonicity) For every (pr, qr) in the trace of (p, q), pr, qr ∈ [p, q]. This and the fact that we have a bounded number of processes may seem to imply that every trace is bounded, but for now we cannot exclude the case that a link is reversed an unbounded number of times between two processes. It will only be implied later when we know that eventually all leaving processes will exit the network.Consider an arbitrary fixed computation of £ÐA. A link that does not change is stable. A steady chain of processes xk, . . . , x0 is a sequence of leaving and not yet gone processes of increasing order with stable links (xi, xi—1). A steady chain is maximal if it cannot be extended to the left or right. See Figure 8 for an illustration. Note thatat every state of the computation, every leaving process is part of at least one maximal steady chain (which might just be a chain consisting of itself). Also, the following lemma holds.Lemma 4. A maximal steady chain can only change in two ways: either (1) process xk exits the network, or (2) the chain is extended to the left or right due to new stable edges. Since the number of processes is bounded, this means that eventually a maximal steady chain is stable, that is, it does not change for the rest of the computation. This is a stable chain.Lemma 5. In every computation of £ÐA, the only stable chain is the empty chain. Proof. Consider the contrary that we have a non-empty stable chain xk, . . . , x0. Our goal will be to prove that eventually there is no incoming link from non-gone processes in PG to xk. This implies that eventually xk has no more messages to process, so NIÐSC will eventually be true. Therefore, xk can exit the network, which contradicts our assumption that the chain is stable.First, suppose there is an incoming link (p, xk) with p < xk. If there is a reversal in the trace of that link, then we end up with a link (xk, pr) with p ≤ pr < xk. If this causes xk to delegate pr away, then due to the Monotonicity Lemma that link will never include xk again. Otherwise, xk stores pr in left , and since a leaving process never reverses its link to left , xk eithe...
Reverse. 3.052 3.422 (FWD) / 3.626 (AWD) FINAL DRIVE 0.599 6TH
Reverse or "reflexive" indemnity: that is, party A reimburses to Party B the losses incurred as the result of the Party B own actions and / or omissions (for example, negligence).