Minrate Sample Clauses

Minrate. Fraction of the total time that the inventory level of an arbitrary part is above or equal to the minimum-level. With minrate the aggregate minrate is meant. The KPIs is measured in process INV. • Utilization: Measures the fraction of the time the servers in process M are occupied. • Total number of parts which are repaired are counted. The number of parts had a higher priority and the remaining number of parts are counted. In process E, it is checked whether the part had a higher priority or not. • Percentage of parts which are repaired within their due-date (only in case of Lead- time). In process E, when the part is repaired and transported it is checked whether its due-date is elapsed or not.
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Minrate. In Figure 7.6a, the minrate and the percentage of parts which are repaired within the lead- time is displayed. The minrate and the percentage of parts which are repaired within the lead-time, both measures the ability of the repair shop, to adhere to the interface agreements made. In the Lead-time To-Be situation, the repair shop is best able to adhere to the agreement to repair parts within the lead-time, hereafter the Min-max To-Be situation and last the Min-max As-Is situation; respectively 92%, 90% and 82%. This performance can be explained by the fact that in the Lead-time model a relatively long lead-time is taken. In the Min-max To-Be situation the turn-around stock and minimum levels are optimized. In this case the minimum levels are well-chosen and therefore it is easier to maintain the inventory level above or equal to the minimum levels. Minrate/ Within due-date 0,90 0,88 0,86 0,84 0,82 0,80 0,78 0,76 0,86 0,90 0,95 0,96 0,97 0,98 Utilization 0,100 0,050 Min−Max To−Be Lead−Time To−Be 0,000 0,86 0,90 0,95 0,96 0,97 0,98 Utilization Percentage orders with prio 1 &2 or emegency lead-time 0,250 0,200 0,150 Min−Max As−Is Ratio Ratio
Minrate. The minrate is the fraction of the time the inventory position is equal or above the minimum level, see Formulas H.9 and H.10. α(S, K) = mi · α (S , K ) (H.9) M  SiΣ−Ki ( ) =  P (Xi = x) if Si − Ki > 0, (H.10) αi Si, Ki i=0  P (Xi = 0) if Si 0 if − Ki = 0, 0 Si − Ki < where α(S, K) is the aggregate minrate for a given turn-around stock vector and a minimum vector. αi(Si, Ki) is the minrate for SKU i, with a given turn-around stock, Si and a minimum level Ki. The exact value of the minrate is equal to 0.8346. In Figure H.7 it can be seen that the two values do not differ significantly. Figure H.7: Comparison of exact minrate with minrate of simulation for Min-max model, using of a t-test (α = 0.95)

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