NORMALITY. No purchase commitment of MW, or by which MW is bound, is materially in excess of the normal, ordinary and usual requirements of the Business or, in the opinion of the Stockholders, is at an excessive price.
NORMALITY. No purchase commitment of TBS, or by which TBS is bound, is materially in excess of the normal, ordinary and usual requirements of the Business or, in the opinion of the Stockholders, is at an excessive price.
NORMALITY. No purchase commitment of WGB, or by which WGB is bound, is materially in excess of the normal, ordinary and usual requirements of the Business or is at an excessive price.
NORMALITY. At least 10 successes [np ≥ 10] and 10 failures [n(1 − p) ≥ 10]. Lec 11 March 3, 2014 9 / 32 Sta102 / BME102 (Xxxxx Xxxxxx) Lec 11 March 3, 2014 10 / 32 Sta102 / BME102 (Xxxxx Xxxxxx) Back to experimental design... Confidence intervals for a proportion Single population proportion Calculating the Confidence Interval Confidence intervals for a proportion Single population proportion The GSS found that 571 out of 670 (85%) of Americans answered the question on experimental design correctly. Estimate (using a 95% confidence interval) the proportion of all Americans who have a good intuition about experimental design? 670 Given: n = 670, pˆ = 571 = 0.85. Are CLT conditions met?
NORMALITY. No purchase commitment of BRITCO, or by which BRITCO is bound, is materially in excess of the normal, ordinary and usual requirements of the Business or, in the opinion of the Stockholders, is at an excessive price.
NORMALITY. Except as set forth in SCHEDULE 3.12, no purchase commitment of CMS, or by which CMS is bound, is in excess of the normal, ordinary and usual requirements of the Business or, in the opinion of the Stockholders, is at an excessive price.
NORMALITY. No purchase commitment of either of DBPC or MDC, or by which either of DBPC or MDC is bound, is in excess of the normal, ordinary and usual requirements of their respective Business or is at an excessive price.
NORMALITY. At least 10 successes (np ≥ 10) and 10 failures (n(1 − p) ≥ 10). Sta102 / BME102 (Xxxxx Xxxxxx) Lec 13 October 15, 2014 10 / 33 Calculating the Confidence Interval Confidence intervals for a proportion Single population proportion . −standard error of the sample proportion is SE = . What isthe We are given that n = 670, pˆ = 0.85, we also just learned that the p(1 p) n 95% confidence interval for this proportion? CI = point estimate ± margin of error = point estimate ± critical value × SE = pˆ ± z∗ × SE . 0.85 × 0.15 Americans, therefore we can assume that one respondent’s response is independent of another.
NORMALITY. At least 10 successes (np ≥ 10) and 10 failures (n(1 − p) ≥ 10). Sta102 / BME102 (Xxxxx Xxxxxx) Lec 14 March 4, 2015 9 / 32 Calculating the Confidence Interval Confidence intervals for a proportion Single population proportion . −standard error of the sample proportion is SE = . What isthe We are given that n = 670, pˆ = 0.85, we also just learned that the p(1 p) n 95% confidence interval for this proportion? CI = point estimate ± margin of error = point estimate ± critical value × SE The GSS found that 571 out of 670 (85%) of Americans answered the question on experimental design correctly. Estimate (using a 95% confidence interval) the proportion of all Americans who have the correct intuition about experimental design? 670 Given: n = 670, pˆ = 571 = 0.85. Are CLT conditions met?
NORMALITY. No purchase commitment of Company, or by which Company is bound, is in excess of the normal, ordinary and usual requirements of the Business or is at an excessive price.
