Proposition 5 Sample Clauses

Proposition 5. The r-DHI assumption holds for Qr A under the assumption that the AS scheme is IND-CPA secure for parameters (x, k, t, r + 1).
AutoNDA by SimpleDocs
Proposition 5. .1. Suppose B is a functor satisfying the hypotheses of Theorem 5.1. Let (CB¯ , s) be the codensity monad of B¯, with distributive law τ and monad structure (CB¯ , η, μ). If Bk+1,k is an isomorphism for some k, then
Proposition 5. 🞐 In the subgame perfect equilibrium for the hub-and-spoke setting with transfers, there is no payoff premium for the hub relative to the common payoff earned by the spokes. Isolated Bilateral with Transfers leton Hub-and-Spoke with Transfers Sing Proposition 6 🞐 For 0 < a < 0.41, the CPNE is the Xxxx equilibrium for the setting in which there is an isolated bilateral agreement. 🞐 For 0.41 < a < 0.514, the CPNE is the Xxxx equilibrium for the hub-and-spoke arrangement. 🞐 For 0.514 < a < 1, the CPNE is the Xxxx equilibrium for the setting in which all nations stand alone in R&D production. Global Welfare ◼ Suppose that global welfare is the sum of all nations’ payoffs: Global Welfare ≡ ∑ u C Isolated Bilateral with Transfers eton Hub-and-Spoke with Transfers Singl Proposition 7 🞐 For sufficiently small attrition rates, constrained global welfare levels improve when green R&D agreements prohibit transfers.
Proposition 5. For some constant probability p, any domain V , and any integer itr, V,p,itr can be UC-realized with statistical security in the a-smt-hybrid model, in constant rounds and in the presence of an adaptive and malicious t-adversary, provided t < n/3.
Proposition 5. 22. The function f (n, m) is multiplicative in m. Proof. Let m1 and m2 be relatively prime positive integers and let P be the set of all prime divisors of m1m2. For i = 1, 2, let Ki be a number field that attains the maximum value for fK(mi). For each prime p in P with p | mi, define Ep = Ki⊗Qp. According to lemma 5.17, there exists a number field K such that K ⊗ Qp Ep for all p ∈ P . For i = 1, 2 and p i p i pk | mi, we have fK(pk) = fK⊗Q (k) = fK ⊗Q (k) = fK (pk) by proposition 5.19. By lemma 5.21, we get fK(mi) = fKi (mi) = f (n, mi) and therefore f (n, m1m2) ≥ fK(m1m2) = f (n, m1)f (n, m2). On the other hand let K′ be a number field of degree n that attains the maximum value for fK(m1m2). Then we also have the bound f (n, m1m2) = fK′ (m1m2) = fK′ (m1)fK′ (m2) ≤ f (n, m1)f (n, m2). Now we prove proposition 5.3, restated here for convenience. Proposition 5.3. The following equality holds for all x. xxx sup log f (n, m) = lim sup log fEt(n, p, k) m→∞ log m pk →∞ k log p Proof. From proposition 5.20 we know log fEt(n, p, k) log f (n, pk) lim sup pk →∞ = lim sup k log p pk →∞ log pk = x. The set of prime powers is a subset of the integers, so we can bound ≤ x lim sup m→∞ log f (n, m) . log m Hence, if x is infinite, we are done. Assume x is finite. Then for all ǫ > 0 we have lim f (n,pk) pk →∞ pk(x+ǫ)
Proposition 5. 9. Let A be a Noetherian ring and B = A[[x1, . . . , xn]] be the A-algebra of formal power series in n variables. Then B is faithfully flat over A.
Proposition 5. .11. The ring Cω is faithfully flat over its subring O. ^ ^ ^O ⊂ O ⊂ C C O Proof. The imbeddings of rings ω show that ω is faithfully flat over by Proposition 5.10, (i) and (iii), and by transitivity (Lemma 5.4). Now the required O ⊂ C ⊂ result follows from the imbeddings ω Lemma 5.5. C^ω by Proposition 5.10, (ii) and The last proposition together with the Malgrange theorem (Proposition 5.6) implies the following result via the transitivity argument (Lemma 5.4).
AutoNDA by SimpleDocs
Proposition 5. 3.1. Let V be a free, finite index, subgroup of E+ of rank n − 1. Then σ∈G u2(V ) = ∑ u2(σ)[V ∶E+] ⊗ σ−1, where u2 = ∑ u2(σ) ⊗ σ−1. σ∈G
Proposition 5. 4.3. Let (nn : Z× → &× )n∈Z be any sequence of weights satisfying np ≡ nn mod p, then inside &K[[q]], p If moreover nb : Z× → &× (En )p ≡ En mod p. n+1 n Kb is the corresponding t-adic weight, then E b corresponds to the sequence (En )n under the isomorphism M + (0) = xxx X + (0)/p of Theorem 5.3.3. n n ∈Z≥0 nb ←− n
Proposition 5.  In the subgame perfect equilibrium for the hub-and-spoke setting with transfers, there is no payoff premium for the hub relative to the common payoff earned by the spokes. Hub-and-Spoke with Transfers Sing Isolated Bilateral with Transfers leton
Time is Money Join Law Insider Premium to draft better contracts faster.